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# How to find the closest value to zero from an array with positive and negative numbers in JavaScript

On the last days, I needed to fill a codingame test that exposed the following problem that needed to be solved: In this exercise, you have to analyze records of temperature to find the closest to zero. Sample temperatures. Here, -1.7 is the closest to 0. Implement the function `closestToZero` to return the temperature closer to zero which belongs to the array `ts`.

• If `ts` is empty, return 0 (zero).
• If two numbers are as close to zero, consider the positive number as the closest to zero (eg. if `ts` contains -5 and 5, return 5).
Input:
• Temperatures are always expressed with floating-point numbers ranging from -273 to 5526.
• `ts` is always a valid array and is never `null`.

## Solution

Based on the exposed data, the following implementation solves the problem:

``````/**
* From a collection of numbers inside an array, returns the closest value to zero.
*/
function closestToZero(numbers) {
if(!numbers.length){
return 0;
}

let closest = 0;

for (let i = 0; i < numbers.length ; i++) {
if (closest === 0) {
closest = numbers[i];
} else if (numbers[i] > 0 && numbers[i] <= Math.abs(closest)) {
closest = numbers[i];
} else if (numbers[i] < 0 && - numbers[i] < Math.abs(closest)) {
closest = numbers[i];
}
}

return closest;
}``````

You can test the code with different examples of your own:

``````let items = [7,-10, 13, 8, 4, -7.2,-12,-3.7,3.5,-9.6, 6.5,-1.7, -6.2,7];
// Result: -1.7
console.log("Result: " + closestToZero(items));

items = [5, 6, 7, 9 , 2, - 2];
// Result: 2
console.log("Result: " + closestToZero(items));

items = [];
// Result: 0
console.log("Result: " + closestToZero(items));``````

Alternatively, one of the solutions of the community includes as well this other option:

``````function closestToZero(numbers)
{
if (numbers.length === 0) return 0;

let closest = numbers;

for(let i = 0; i < numbers.length;i++){
let number = numbers[i];
let absNumber =  Math.abs(number);
let absClosest = Math.abs(closest);

if (absNumber < absClosest)
{
closest = number;
}
else if (absNumber === absClosest && closest < 0)
{
closest = number;
}
}

return closest;
}``````

Happy coding ❤️!